What is sum of all digits from 5 to 10

10+9+8+7+6+5=45

The answer is 45

the sum of 1 + 2 + 3 + 4 + .....+ n = (n)(n+1)/2

So 1+2+3....+10 = (10)(11)/2 = 55

but since you only want 5-10, we subtract the first 4.

1+2+3+4 = (4)(5)/2 = 10

So 55-10 = 45 is the answer. You can use this method to find the sum of any n consecutive integers.

You can't figure this one out? Oh dear...
5+6+7+8+9+10 = 45

45

Your mom;)

5+6+7+8+9+10= 45

5+6+7+8+9+10=45 <--- This is your answer!