to solve the quadratic equation 7x^2-2=3x, we can substitute values for a,b and c into the quadratic formula. which is the true statement
A) a=7,b=-3,c=-2
B) a=7, b=-2,c=-3
C) a=7, b=3, c=-2
D) a=7, b=3, c=2
A) a=7,b=-3,c=-2
B) a=7, b=-2,c=-3
C) a=7, b=3, c=-2
D) a=7, b=3, c=2
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7x² - 2 = 3x
7x² - 3x - 2 = 0 {subtracted 3x from both sides}
a = 7, b = -3, c = -2
A.)
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7x² - 3x - 2 = 0 {subtracted 3x from both sides}
a = 7, b = -3, c = -2
A.)
For more help like this, ask the house: http://www.algebrahouse.com
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Well, I would just subtract 3x from both sides giving:
7x^2 - 3x - 2 = 0
Now, from this equation the answer should be pretty clear. Simply look at the coefficients of each term. a = 7, -3 = b, and -2 = c or choice A).
7x^2 - 3x - 2 = 0
Now, from this equation the answer should be pretty clear. Simply look at the coefficients of each term. a = 7, -3 = b, and -2 = c or choice A).
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A.