0.07x – 0.01y = 2.3
0.28x + 0.13y = 17.7
0.28x + 0.13y = 17.7
-
the substitution method says:
1. take one of the 2 equations and solve for x in terms of y or y in terms of x.
2. plug this value into the other equation.
3. plug that value into one of the other equations.
lets multiply everything by 100 to get rid of the decimals.
7x - y = 230
and
28x + 13y = 1770
start with the first equation.
solve for y in terms of x.
-y = -7x + 230
y = 7x - 230
now plug this into the second equation.
28x + 13y = 1770
28x + 13 (7x - 230) = 1770
28x + 91 x -2990 = 1770
119 x - 2990 = 1770
119 x = 4760
x= 40.
now plug this into one of the equations
7x - y = 230
7*40 - y = 230
280 - y = 230
-y = -50
y = 50
so, the solution to this system of equations is x = 40 , y = 50 or the ordered pair (40, 50).
1. take one of the 2 equations and solve for x in terms of y or y in terms of x.
2. plug this value into the other equation.
3. plug that value into one of the other equations.
lets multiply everything by 100 to get rid of the decimals.
7x - y = 230
and
28x + 13y = 1770
start with the first equation.
solve for y in terms of x.
-y = -7x + 230
y = 7x - 230
now plug this into the second equation.
28x + 13y = 1770
28x + 13 (7x - 230) = 1770
28x + 91 x -2990 = 1770
119 x - 2990 = 1770
119 x = 4760
x= 40.
now plug this into one of the equations
7x - y = 230
7*40 - y = 230
280 - y = 230
-y = -50
y = 50
so, the solution to this system of equations is x = 40 , y = 50 or the ordered pair (40, 50).
-
Standard form: 7/100x-1/100y=2.3; 7/25x+13/100y=17.7;
substitute/eliminate x = +1/7y+230/7
substitute/eliminate y = +50
Solution: x = 40; y = 50;
or (x, y) = (40, 50)
substitute/eliminate x = +1/7y+230/7
substitute/eliminate y = +50
Solution: x = 40; y = 50;
or (x, y) = (40, 50)