How can you prove the identity of tan(x+pi) - tan(pi-x) = 2tanx

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How can you prove the identity of tan(x+pi) - tan(pi-x) = 2tanx

[From: ] [author: ] [Date: 11-06-27] [Hit: ]

tan(x + pi) = tan(x)
tan(pi - x) = - tan(x)
tan(pi+x) - tan(pi-x) = tan(x) + tan(x) = 2tan(x)

tan (x + pi) = tan x
tan (pi - x) = - tan x

tan x - (- tan x) = 2 tan x

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