16x^2-25
would the answer be (x+4)(x-5)?
And:
2x^3y+10x^2y+12xy
^ i seriously don't know what to do with that
would the answer be (x+4)(x-5)?
And:
2x^3y+10x^2y+12xy
^ i seriously don't know what to do with that
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2x^3 y + 10x^2 y + 12xy
there is a common factor of (2xy)
2xy(x^2 + 5x + 6) = 2xy(x + 3)(x + 2)
check by multiplying...
why do you think your answer to 16x^2 - 25 is correct ? It can't be correct...x * x = x^2
where is 16x^2
16x^2 - 25 = (4x + 5)(4x - 5)
this is the difference of two squares...a very important concept !
read your textbook...practice...practice a lot !
there is a common factor of (2xy)
2xy(x^2 + 5x + 6) = 2xy(x + 3)(x + 2)
check by multiplying...
why do you think your answer to 16x^2 - 25 is correct ? It can't be correct...x * x = x^2
where is 16x^2
16x^2 - 25 = (4x + 5)(4x - 5)
this is the difference of two squares...a very important concept !
read your textbook...practice...practice a lot !
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16x^2 - 25 = (4x + 5)(4x + 5) = (4x + 5)^2
For the second one, they all have a common term of 2xy, so factor that out first.
2x^3y + 10x^2y + 12xy
2xy(x^2 + 5x + 6)
2xy(x + 2)(x + 3)
Cheers!
For the second one, they all have a common term of 2xy, so factor that out first.
2x^3y + 10x^2y + 12xy
2xy(x^2 + 5x + 6)
2xy(x + 2)(x + 3)
Cheers!
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first one: 16x^2 - 25 = (4x + 5)(4x + 5) this is a perfect sq trinomial
second one: 2x^3y + 10x^2y + 12xy
2xy(x^2 + 5x + 6)
2xy(x + 2)(x + 3)
second one: 2x^3y + 10x^2y + 12xy
2xy(x^2 + 5x + 6)
2xy(x + 2)(x + 3)
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(4x+5)(4x-5)
2xy(x+6)(x-1)
2xy(x+6)(x-1)
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(4x+5)(4x-5) is your first one