What is the first six terms of each of these sequences.
1. ) an=6-n
2.) f(n)=n^3+2
3.) an=4^(n-1)
1. ) an=6-n
2.) f(n)=n^3+2
3.) an=4^(n-1)
-
1)
a1 = 6 - 1 = 5
a2 = 6- 2 = 4
.
.
a6 = 6-6 =0
2)
f(1) = 1^3+2 = 3
f(2) = 2^3+2=10
.
.
.
f(6) = 6^3+2=218
3)
a1 = 4^(1-1) = 4^0 = 1
a2 = 4^(2-1) = 4
.
.
.
a6 = 4^(6-1) = 1024
a1 = 6 - 1 = 5
a2 = 6- 2 = 4
.
.
a6 = 6-6 =0
2)
f(1) = 1^3+2 = 3
f(2) = 2^3+2=10
.
.
.
f(6) = 6^3+2=218
3)
a1 = 4^(1-1) = 4^0 = 1
a2 = 4^(2-1) = 4
.
.
.
a6 = 4^(6-1) = 1024