Logs Need Help (Pre Calc)
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Logs Need Help (Pre Calc)

[From: ] [author: ] [Date: 11-05-17] [Hit: ]
.12x = 2x + 8 ← so far, so good. then.........
27^4x= 9^x+4
^
(3^3)^4x= (3^2)x+4>>>> 3^12x=3^2x+8>>>> 12x=2x+8>>>>>> 4x/2x=2x/2x= x=2 what am i doing wrong....

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27^(4x) = 9^(x + 4)
3^(12x) = 3^(2x + 8)
12x = 2x + 8 ← so far, so good. then...
6x = x + 4
5x = 4
x = 4/5

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