Math homework help!!

heres the question..Write an equation that represents the line that passes through the points (5,4) and (-5,0)

show step by step pleaseeeee! thank youu

The equation for a straight line is:

y=Mx+b
where M=slope
M=(the change in y/the change x)

From the 2 points:
change in x = 5 - (-5) = 10
change in y = 4 - 0 = 4

so the slope = M = 4/10 = 2/5

To find be you have
y = (2/5)x + b

plug in either point (you will get the same answer), and solve for b
0 = (2/5)(-5) + b => b = 2
4 = (5/2)(5) +b => b = 2

Your equation therefore is
y=(2/5)x +2

(5,4)
(-5,0)

Use the formula: y=mx+b
m is the slope, and b is the y-intercept

Substitute in the values of x and y into this formula to find the slope m:
m = (0 -(4))/(-5 -(5))

Next, substitute the value of y into the formula:
4 = ((2)/(5)) * (5) + b

Find b:
(4) = ((2)/(5)) * (5) + b
((2)/(5))*(5) +b = 4
((2)/(5))(5) +b = 4
2 + b = 4
b + 2 = 4
b + 2 -2 = 4 -2
b=2

Substitute the values into y=mx+b:

y = (2x/5) + 2