Solve each equation by root property (10 POINTS!)
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > Solve each equation by root property (10 POINTS!)

Solve each equation by root property (10 POINTS!)

[From: ] [author: ] [Date: 11-05-16] [Hit: ]
(y-4)^2+7=0 has no real roots since (y-4)^2 is never negative. If you include complex(imaginary) numbers the solutions are 4+i*sqrt(7) and 4-i*sqrt(7).......
1. (7b - 4)² = 144

2. (2p + 5)² = 32

3. (y - 4)² + 7 = 0

-
Not sure what you mean by "root property" but these equations imply:

(7b-4)^2=144-> 7b-4=+12 or 7b-4=-12-> b=16/7 or b=-8/7.

(2p+5)^2=32-> 2p+5=sqrt(32) or 2p+5=-sqrt(32)->p=(1/2)*[4sqrt(2)-5] or p=(1/2)*[-4sqrt(2)-5],
sincesqrt(32)=sqrt(4*4*2)

(y-4)^2+7=0 has no real roots since (y-4)^2 is never negative. If you include complex(imaginary) numbers the solutions are 4+i*sqrt(7) and 4-i*sqrt(7).

Hope this helps

-
1square both sides the solve

2 square both sides then solve

3 subtract 7 both sides then square both sided
1
keywords: root,Solve,property,by,10,POINTS,each,equation,Solve each equation by root property (10 POINTS!)
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .