1. (7b - 4)² = 144
2. (2p + 5)² = 32
3. (y - 4)² + 7 = 0
2. (2p + 5)² = 32
3. (y - 4)² + 7 = 0
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Not sure what you mean by "root property" but these equations imply:
(7b-4)^2=144-> 7b-4=+12 or 7b-4=-12-> b=16/7 or b=-8/7.
(2p+5)^2=32-> 2p+5=sqrt(32) or 2p+5=-sqrt(32)->p=(1/2)*[4sqrt(2)-5] or p=(1/2)*[-4sqrt(2)-5],
sincesqrt(32)=sqrt(4*4*2)
(y-4)^2+7=0 has no real roots since (y-4)^2 is never negative. If you include complex(imaginary) numbers the solutions are 4+i*sqrt(7) and 4-i*sqrt(7).
Hope this helps
(7b-4)^2=144-> 7b-4=+12 or 7b-4=-12-> b=16/7 or b=-8/7.
(2p+5)^2=32-> 2p+5=sqrt(32) or 2p+5=-sqrt(32)->p=(1/2)*[4sqrt(2)-5] or p=(1/2)*[-4sqrt(2)-5],
sincesqrt(32)=sqrt(4*4*2)
(y-4)^2+7=0 has no real roots since (y-4)^2 is never negative. If you include complex(imaginary) numbers the solutions are 4+i*sqrt(7) and 4-i*sqrt(7).
Hope this helps
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1square both sides the solve
2 square both sides then solve
3 subtract 7 both sides then square both sided
2 square both sides then solve
3 subtract 7 both sides then square both sided