That it has these following characteristics. (There are no other characteristics, these are the exact ones provided.)
Real number coefficients.
Zeros at 2, -5, 2+i
f(0) = -150
Please show any work so I can understand. 10 points to best answer! Thanks!
Real number coefficients.
Zeros at 2, -5, 2+i
f(0) = -150
Please show any work so I can understand. 10 points to best answer! Thanks!
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The complex number 2 + i is a root, so its conjugate, 2 - i, must also be a root. That gives us four known roots. There may be others, and some of these roots may be repeated.
f(x) = p(x)(x - 2)(x + 5)[x - (2 + i)][x - (2 - i)], where p(x) is a polynomial
f(x) = p(x)(x - 2)(x + 5)(x² - 4x + 5)
f(0) = -150
p(0)(-2)(5)(5) = -150
-50p(0) = -150
p(0) = 3
There are any number of polynomials fitting the bill. Here are a few that work:
f(x) = 3(x - 2)(x + 5)(x² - 4x + 5)
f(x) = (x + 3)(x - 2)(x + 5)(x² - 4x + 5)
f(x) = (x² + 3)(x - 2)(x + 5)(x² - 4x + 5)
f(x) = p(x)(x - 2)(x + 5)[x - (2 + i)][x - (2 - i)], where p(x) is a polynomial
f(x) = p(x)(x - 2)(x + 5)(x² - 4x + 5)
f(0) = -150
p(0)(-2)(5)(5) = -150
-50p(0) = -150
p(0) = 3
There are any number of polynomials fitting the bill. Here are a few that work:
f(x) = 3(x - 2)(x + 5)(x² - 4x + 5)
f(x) = (x + 3)(x - 2)(x + 5)(x² - 4x + 5)
f(x) = (x² + 3)(x - 2)(x + 5)(x² - 4x + 5)