HELP!
Find the standard form of the equation of the specified ellipse.
7. Center: (0,0) Foci: ( 0, plus and negative 2 square root of15) , Vertices: (0, plus and negative 8)
Find the standard form of the equation of the specified ellipse.
7. Center: (0,0) Foci: ( 0, plus and negative 2 square root of15) , Vertices: (0, plus and negative 8)
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Since the vertices are on the y-axis and the center is (0, 0) the equation of the ellipse is of the form
y^2 / a^2 + x^2 / b^2 = 1
where
a = 8, c = 2sqrt(15), and a^2 - b^2 = c^2
Then a^2 = 8^2 = 64 and c^2 = (2sqrt(15))^2 = 60.
64 - b^2 = 60
-b^2 = 60 - 64
-b^2 = -4
b^2 = 4
Thus, the answer is
y^2 / 64 + x^2 / 4 = 1
y^2 / a^2 + x^2 / b^2 = 1
where
a = 8, c = 2sqrt(15), and a^2 - b^2 = c^2
Then a^2 = 8^2 = 64 and c^2 = (2sqrt(15))^2 = 60.
64 - b^2 = 60
-b^2 = 60 - 64
-b^2 = -4
b^2 = 4
Thus, the answer is
y^2 / 64 + x^2 / 4 = 1