This is for a GRE practice test question, and I am either thinking of the wrong information, the answer are wrong... Im thinking P1/T1=P2/T2...but I get P2= 32.6....which isnt listed...
QUESTION:
The tire of an automobile is filled with air to a gauge pressure of 35 psi at 20°C in the summer time. What is the gauge pressure in the tire when the temperature falls to 0°C in the winter time? Assume that the volume does not change and that the atmospheric pressure is a constant 14.70 psi.
49.7 psi
35 psi
14.7 psi
31.6 psi
46.3 psi
QUESTION:
The tire of an automobile is filled with air to a gauge pressure of 35 psi at 20°C in the summer time. What is the gauge pressure in the tire when the temperature falls to 0°C in the winter time? Assume that the volume does not change and that the atmospheric pressure is a constant 14.70 psi.
49.7 psi
35 psi
14.7 psi
31.6 psi
46.3 psi
-
It's 31.6
P1 = 35 + 14.7 = 49.7
T1 = 20 + 273.15 = 293.15
T2 = 273.15
P1/T1 = 0.1696
P2 = T2 * 0.1696 = 46.32 absolute
P2 gauge = 46.32 - 14.7 = 31.6
P1 = 35 + 14.7 = 49.7
T1 = 20 + 273.15 = 293.15
T2 = 273.15
P1/T1 = 0.1696
P2 = T2 * 0.1696 = 46.32 absolute
P2 gauge = 46.32 - 14.7 = 31.6