A vertical spring stretches 3.9cm when a 10 gram object is hung from it. The object is replaced with a block of mass 25g that oscillates up and down in a simple harmonic motion.
If you can do the problem and show how its done then great.
My main question is about the Force constant.
K=mg/x
now does the force constant always remain the same?
So if the force constant for the 10gram object = 2.51 N/m
Will that be the force constant for the 25gram object?
If you can do the problem and show how its done then great.
My main question is about the Force constant.
K=mg/x
now does the force constant always remain the same?
So if the force constant for the 10gram object = 2.51 N/m
Will that be the force constant for the 25gram object?
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k is a function of the construction of the spring and has nothing to do with the mass attached to it.
k = mg/x = .01*9.8/.039 = 2.51 N/m
With m = 25 g, the system will oscillate with a period T = 2π√[m/k] = .627 sec
k = mg/x = .01*9.8/.039 = 2.51 N/m
With m = 25 g, the system will oscillate with a period T = 2π√[m/k] = .627 sec
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yes ,force constant always remain the same
because material is same which made of spring
If material change otherwise put some heat or cool to the spring
So the force constant will be change ......
because material is same which made of spring
If material change otherwise put some heat or cool to the spring
So the force constant will be change ......