What is the power output of an electric motor that lifts an elevator with a mass of 1500 kg at a speed of 0.750 m/s.
(1500)(9.81) = 14715 N
(14715)(0.75) = 11036.25 W
11036 / 1000 = 11.0 kW
(1500)(9.81) = 14715 N
(14715)(0.75) = 11036.25 W
11036 / 1000 = 11.0 kW
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Looks OK :>)
comment: in practice the power OUTPUT of motors is usually given in units of horsepower; it's the power INPUT that's given in KW or KVA {kilovolt-amperes}.
comment: in practice the power OUTPUT of motors is usually given in units of horsepower; it's the power INPUT that's given in KW or KVA {kilovolt-amperes}.