I am not sure what equation to use... I need to figure out the amount of force required to pull something (a box, for example) depending on the angle of the rope... like if it is attached at the top or middle of the box.
I know the equations for pushing and pulling things and stuff on inclines but I'm not sure how to factor the rope and the angle of the rope into this...?
I know the equations for pushing and pulling things and stuff on inclines but I'm not sure how to factor the rope and the angle of the rope into this...?
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IDEAS of VECTORS will come to your rescue......
CONSIDER a block of mass 'm' lying on a smooth horizontal surface. let the rope attached make an angle say 'φ' with the horizontal of the smooth surface where the block is lying.
now let the force required be 'F'. using the ideas of vectors we will resolve this F into the mutually perpendicular components.
F along x is Fx=mgcosφ (this is along the surface where the block is kept)
and along Y is Fy=mgsinφ (along the vertical)
now using NEWTONS second law F=squareroot{ (FX)^2 +(Fy)^2 }
this F=ma...where a is the required acceleration(case dependent may be different)
CONSIDER a block of mass 'm' lying on a smooth horizontal surface. let the rope attached make an angle say 'φ' with the horizontal of the smooth surface where the block is lying.
now let the force required be 'F'. using the ideas of vectors we will resolve this F into the mutually perpendicular components.
F along x is Fx=mgcosφ (this is along the surface where the block is kept)
and along Y is Fy=mgsinφ (along the vertical)
now using NEWTONS second law F=squareroot{ (FX)^2 +(Fy)^2 }
this F=ma...where a is the required acceleration(case dependent may be different)
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Thank u !
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