Hi, I don't understand how to do this problem. I am having a test soon an this so I need to understand how to do it, please show you work or how you did it.
1. The numbers 2, 4, 6, and 8 are a set of four consecutive even numbers. Suppose the sum of five consecutive even numbers is 320. What is the smallest of the five numbers?
thank youuu :DD
1. The numbers 2, 4, 6, and 8 are a set of four consecutive even numbers. Suppose the sum of five consecutive even numbers is 320. What is the smallest of the five numbers?
thank youuu :DD
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Make x be your smallest consecutive even number. So your 5 consecutive even numbers would be:
x
x+2
x+4
x+6
x+8
The sum of all of these numbers is 320 so:
x+(x+2)+(x+4)+(x+6)+(x+8) = 320
320=5x+20
300=5x
x=60
x
x+2
x+4
x+6
x+8
The sum of all of these numbers is 320 so:
x+(x+2)+(x+4)+(x+6)+(x+8) = 320
320=5x+20
300=5x
x=60
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So lets take a random number n, the next consecutive number is n + 1. Let's say that n is an even number, then the next even consecutive number is n + 2. Using that logic we can find 5 consecutive even numbers
n
n + 2
n + 4
n + 6
n + 8
So your problem is saying, the sum of those 5 numbers is 320 so
n + n + 2 + n + 4 + n + 6 + n + 8 = 320
From there you can add up all the numbers and n's and then solve for n
Once you have the solution for n, you can then plug it into all the other numbers and find out what the other 4 consecutive even numbers are. Double check your work and add them all up to make certain it adds up to 320 and then you're done
n
n + 2
n + 4
n + 6
n + 8
So your problem is saying, the sum of those 5 numbers is 320 so
n + n + 2 + n + 4 + n + 6 + n + 8 = 320
From there you can add up all the numbers and n's and then solve for n
Once you have the solution for n, you can then plug it into all the other numbers and find out what the other 4 consecutive even numbers are. Double check your work and add them all up to make certain it adds up to 320 and then you're done