Convert the point from polar to rectangular form:
(√3, π/6)
(√3, π/6)
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r = √3
θ = π/6
x = r cos(θ) = √3cos(π/6)
x = √3(√3/2) = 3/2
y = r sin(θ) = √3sin(π/6)
y = (1/2)√3
(x, y) = (3/2,√3 /2)
θ = π/6
x = r cos(θ) = √3cos(π/6)
x = √3(√3/2) = 3/2
y = r sin(θ) = √3sin(π/6)
y = (1/2)√3
(x, y) = (3/2,√3 /2)
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1.5, .86