Impedance equivalent help
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Impedance equivalent help

[From: ] [author: ] [Date: 13-04-21] [Hit: ]
40 – j20-I just told someone else they need to learn hpw to do math with comlex numbers.Was it you?See: http://en.wikipedia.......
I have a 50 ohm resistor parallel with a 50 micro F capacitor. I understand how to get Zc = -j100, but my solutions manual for the Zeq of the two is giving 40-j20. I can get to -j100/(1-j2), but the solution jumps right from there to 40-j20.

Assuming I am not aware of some algebra steps to get me to the answer so I would greatly appreciate that explanation. I am also aware of the complex numbers identities like j^2 = -1.

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–(j100) / (1 – j2)
multiply by the complex conjugate over itself
[ –(j100) / (1 – j2) ] [ (1+j2) / (1+j2) ]
[ –j100 – j²200 ] / [ 1 – 4j² ]
(200 – j100 ) / ( 5)
40 – j20

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I just told someone else they need to learn hpw to do math with comlex numbers. Was it you? See: http://en.wikipedia.org/wiki/Complex_num…
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