How to calculate resistance with the given info

A 10 µF capacitor is charged by a 10.0 volt battery through a resistance R. The capacitor reaches a potential difference of 4.0 V in a time 3.0 s after charging begins. Determine R.

The characteristic equation is:
Vo(t)=10*{1 - e^-t/(CR)}
So,
4=10*{1 - e^-3/(10*10^(-6)*R)}
0.4 - 1 = - e^-3/(10*10^(-6)*R)
0.6=e^-3/(10*10^(-6)*R)
ln(0.6)=-3/(10*10^(-6)*R)
R= -3/(10*10^(-6)*ln(0.6))
=587285 ohm