Can the discharge coefficient over a triangular weir be calculated as:
Cd=Q(volume flow rate coming into reservoir)/Q(over weir)
Where Q(over weir) is calculated as Q=(8/15)*sqrt(2g)*tan(theta/2)*H^(5/2)
Cd=Q(volume flow rate coming into reservoir)/Q(over weir)
Where Q(over weir) is calculated as Q=(8/15)*sqrt(2g)*tan(theta/2)*H^(5/2)
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I would say yes. Keep in mind the value varies with H (depth of upstream water surface above wier). Not sure how you are getting the inflow/outflow. And if its for long term problems you need to consider evaporation and infiltration.
According to "Handbook of Hydraulics" by Brater and King 6th ed the equation for flow over triangular weir is:
Q = CLH^1.5
and the values of C vary from 3.88 to 2.93 depending on the angle of the downstream face and the value of H from 0.2 to 1.5 feet deep. So you dont need to use theta (angle of weir?) as it will be built into your C.
PS You know the inflow? so you just use that for the Q over the weir and solve for C. Account for any other losses as reqd. So Qin - losses = Qout = Q over weir. If its a large reservoir you may need to include any storage in the reservior due to H as losses.
According to "Handbook of Hydraulics" by Brater and King 6th ed the equation for flow over triangular weir is:
Q = CLH^1.5
and the values of C vary from 3.88 to 2.93 depending on the angle of the downstream face and the value of H from 0.2 to 1.5 feet deep. So you dont need to use theta (angle of weir?) as it will be built into your C.
PS You know the inflow? so you just use that for the Q over the weir and solve for C. Account for any other losses as reqd. So Qin - losses = Qout = Q over weir. If its a large reservoir you may need to include any storage in the reservior due to H as losses.