I am in a rush to finish this assignment and get it submitted, but i'm totally stumped!! Please help!!
Ammonia is produced from its elements in a formation reaction from hydrogen and nitrogen. If 8.90 x 10^24 molecules of ammonia are produced in the reaction.
a) What number of moles of ammonia are produced in the reaction?
b) What volume of ammonia is present after the reaction if the reaction vessel is at SATP?
c) What volume of hydrogen reacted?
Ammonia is produced from its elements in a formation reaction from hydrogen and nitrogen. If 8.90 x 10^24 molecules of ammonia are produced in the reaction.
a) What number of moles of ammonia are produced in the reaction?
b) What volume of ammonia is present after the reaction if the reaction vessel is at SATP?
c) What volume of hydrogen reacted?
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a) divide 8.90 x 10^24 BY 6.02 x 10^23 to get moles of ammonia
b) At SATP the formula is moles = v / V where V = 24.8 L/mol of gas so v = n x V
c) According to the balanced equation for every 2 moles of NH3 produced you only need 1 mole of N2
So take the number of moles calculated in a) and divide it by two. The apply v = n x V again where V is 24.8 L/mol
b) At SATP the formula is moles = v / V where V = 24.8 L/mol of gas so v = n x V
c) According to the balanced equation for every 2 moles of NH3 produced you only need 1 mole of N2
So take the number of moles calculated in a) and divide it by two. The apply v = n x V again where V is 24.8 L/mol
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a use particles to moles
b now us moles to volume
c use the ratio of moles of H2 to moles of NH3 just multiply by 3/2 x B
http://www.kentchemistry.com/links/GasLa…
b now us moles to volume
c use the ratio of moles of H2 to moles of NH3 just multiply by 3/2 x B
http://www.kentchemistry.com/links/GasLa…