In Rectilinear Motion, the velocity of a particle is given by Vx = x and s = 1m at t = 0, determine the
position as a function of time.
Please give explanation.
Thank you so much!!!
position as a function of time.
Please give explanation.
Thank you so much!!!
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I'll call Vx simply 'v', for neatness.
And I'll assume s and x are the same thing (displacmenet)
v = dx/dt
so
dx/dt = x
dx/x = dt
Integrate
ln(x) = t + C
When t=0, x=1 so
ln(1) = 0 + C
C = 0 (since ln(1) =0)
So t = ln(x)
x = e^t
And I'll assume s and x are the same thing (displacmenet)
v = dx/dt
so
dx/dt = x
dx/x = dt
Integrate
ln(x) = t + C
When t=0, x=1 so
ln(1) = 0 + C
C = 0 (since ln(1) =0)
So t = ln(x)
x = e^t
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X=16t²+pi/2t+1