A student uses 2.38g of magnesium hydroxide to make up 100mL of solution. What is the molar concentration of the solution? Is this possible, why or why not?
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There's no way you can dissolve 2.38 g of Mg(OH)2 in 100 mL of water. You'd be lucky to dissolve 1 mg! If you COULD do it,
2.38 g Mg(OH)2 x (1 mole Mg(OH)2 / 58.3 g Mg(OH)2) = 0.0408 moles Mg(OH)2
Molarity Mg(OH)2 = 0.0408 moles / 0.100 L = 0.408 M
2.38 g Mg(OH)2 x (1 mole Mg(OH)2 / 58.3 g Mg(OH)2) = 0.0408 moles Mg(OH)2
Molarity Mg(OH)2 = 0.0408 moles / 0.100 L = 0.408 M