How do put this equation in the calculator? [H3O+] = 8.4 x 10^-5 M pH =

Anybody? I am using a non-scientific calculator too.

[H+] = 8.4x10^-5
so pH =- log[H+]
= - log[ 8.4 x10^-5]
= 5 - log8.4
= 5- 0.9242
pH = 4.0757 answer

http://www.kentchemistry.com/links/Acids…

just watch the calculator on this short pH video

you need a sci. calc for logs