Please help with emperical formulae!!!! pleaseeee
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Please help with emperical formulae!!!! pleaseeee

[From: ] [author: ] [Date: 12-06-26] [Hit: ]
what is the molecular formulae?Please do show the steps and what is meant by 400g/mol.mole of C = 18.0g x (1 mol C/12.01g) = 1.mole of H = 2.......
Determine the emperical formulae of a compound with the following composition by mass: 18% C, 2.5% H, 63.5% I and 16% O. If this compound has a molar mass of 400g/mol, what is the molecular formulae?
Please do show the steps and what is meant by 400g/mol.

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Assume a 100-gram sample:

mole of C = 18.0g x (1 mol C/12.01g) = 1.50 moles

mole of H = 2.50g x (1 mol H/1.01g) = 2.48 moles

mole of I = 63.5g x (1 mol I/126.90g) = 0.500 mole

mole of O = 16.0g x (1 mol O/16.00g) = 1.00 mole

C: 1.50/.500 = 3

H: 2.48/.500 = 4.96 ≈ 5

I: .500/.500 = 1

O: 1.00/.500 = 2

Empirical Formula is : C3H5IO2

n = (400 g/mol)/199.98 g/mol = 2

Molecular Formula = C3H5IO2 x (2) = C6H10I2O4

Thank you...

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Nesteve JOHN's answer is correct...
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