AP Chemistry Solubility Equilibrium
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AP Chemistry Solubility Equilibrium

[From: ] [author: ] [Date: 12-03-30] [Hit: ]
The answer should be 2.for a saturated solution,therefore,x = [Fe 2+] = 2.......
I am having trouble on this homework problem, can you please help me:

If the Ksp for Iron (II) sulfide is 6E-18, what is the concentration of Fe2+ in a saturated solution?

Wouldn't you just take the square root of 6E-18? I tried that, but it says incorrect answer. Please explain how to get the right answer.

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Take the square root of 6E-18, as usual to get 2.449489743e-9.
Then, because of the specific heat involved in the reaction, divide this answer by 1.01
The answer should be 2.425237369e-9

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if Ksp = 6x10^-18 then:
6x10^-18 = [Fe2+][S2-]

for a saturated solution, Q = Ksp
therefore, [Fe 2+]

6x10^-18 = x^2
x = [Fe 2+] = 2.45x10^-9M
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