A very flexible helium-filled balloon is released from the ground into the air at 293 K. The initial volume of the balloon is 5.00 L, and the pressure is 760. mmHg. The balloon ascends to an altitude of 20 km, where the pressure is 76.0 mmHg and the temperature is 223 K. What is the new volume, (v2), of the balloon in liters, assuming it doesn't break or leak?
equation is P1V1/ T1 = P2V2/T2
and you have o convert the temp to
equation is P1V1/ T1 = P2V2/T2
and you have o convert the temp to
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The units are all right. They don't need converting.
76 x V2/ 223 = 760 x 5/ 293
V2 = 10 x (223/293) x 5
38.05 liters
76 x V2/ 223 = 760 x 5/ 293
V2 = 10 x (223/293) x 5
38.05 liters
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(760 x 5) /293= (76 x v2)/223
v2= 38.1 L
v2= 38.1 L