I desperately need help solving 4 Chemistry answers please!

1.When the following equation is balanced the smallest possible integers, What is the number in front of the substance at the end being +H2:

Sn + NaOH → Na2SnO2 + H2

a.1, b. 2, c. 3, d. 4, or e. 5 ?


2.When the following equation is balanced the smallest possible integers, What is the number in front of the substance at the end being +KNO3:

Pb(NO3)2 + K2CO3 → PbCO3 + KNO3

a. 5, b. 4, c. 3, d. 2, or e. 1 ?


3.When the following equation is balanced the smallest possible integers, What is the number in front of the substance at the end being + HCI:

PCI5 + H2O → H3PO4 + HCI

a. 1, b. 2, c. 3, d. 4, or e. 5 ?


4.When the following equation is balanced the smallest possible integers, What is the number in front of the substance at the second part of the equation being + O2:

C2H6 + O2 → CO2 + H2O

a. 1, b. 2, c. 4, d. 6, or e. 7 ?

Question 1: A
Question 2: D
Question 3: E
Question 4: E

Note: Please do not let Yahoo answers nor its users spoon-feed you next time.

1.When the following equation is balanced the smallest possible integers, What is the number in front of the substance at the end being +H2:

Sn(s) + 2NaOH(aq) >>>>>>>>>>>>>> Na2SnO2(s) + H2(g)

The answer is a.

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2.When the following equation is balanced the smallest possible integers, What is the number in front of the substance at the end being +KNO3:

Pb(NO3)2(aq) + K2CO3(aq) >>>>>>>>>>>>>>>> PbCO3(s) + 2KNO3(aq)

The answer is d.

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3.When the following equation is balanced the smallest possible integers, What is the number in front of the substance at the end being + HCI:

PCI5(l) + 4H2O(l) >>>>>>>>>>>>> H3PO4(aq) + 5HCI(aq)

The answer is e.

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4.When the following equation is balanced the smallest possible integers, What is the number in front of the substance at the second part of the equation being + O2:

2C2H6(g) + 7O2(g) >>>>>>>>>>>>>>> 4CO2(g) + 6H2O(g)

The answer is e.