Can you show me how to convert this into exponential form?
y=-1+log(base2) x
Thanks!
y=-1+log(base2) x
Thanks!
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y = −1 + log₂(x)
y + 1 = log₂(x)
2^(y+1) = 2^log₂(x)
2^(y+1) = x
Mαthmφm
y + 1 = log₂(x)
2^(y+1) = 2^log₂(x)
2^(y+1) = x
Mαthmφm
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Google it honey...
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Log^a x=y
To
X=a^y
Just match it up
To
X=a^y
Just match it up