If an object is free falling, from what height would it need to be dropped to reach a speed of 7.0m/s before reching the ground.
so u need D A is 9,8 for gravety, Vf is 70 Vi is 0
so u need D A is 9,8 for gravety, Vf is 70 Vi is 0
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Use the equation vf^2=vi^2+2ad and plug in.
vf^2=vi^2+2ad
7.0^2=0^2+2(9.8)d
49=19.6d
d=2.5
The answer is 2.5 meters.
vf^2=vi^2+2ad
7.0^2=0^2+2(9.8)d
49=19.6d
d=2.5
The answer is 2.5 meters.
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You are correct in your assumptions. Now what you do with the given information is plug into a linear acceleration formula. For this case, it is best to use 2a*deltaX = vf^2 - vi^2. Plug in your information.
2(9.8)x = 49
x = 2.5 meters.
2(9.8)x = 49
x = 2.5 meters.