As part of my Chemistry homework I have to answer this question:
What is the concentration of HCl(aq) if 25.00cm3 of 0.552 mol dm-3 NaOH is needed to neutralise 18.75cm3 of the acid.
Does anyone know where I should begin with this? Any help would be much appreciated :)
What is the concentration of HCl(aq) if 25.00cm3 of 0.552 mol dm-3 NaOH is needed to neutralise 18.75cm3 of the acid.
Does anyone know where I should begin with this? Any help would be much appreciated :)
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Find the moles of base used. moles = M x L 0.552 x 0.025 = 0.0138 moles
Molarity of acid = moles / L =0.0138 / 0.01875 = 0.736 M.
Molarity of acid = moles / L =0.0138 / 0.01875 = 0.736 M.