Can someone please explain this to me?
A cubic lattice has the atom X at teach of the corners, Y on each face center, and Z on each edge center. Determine the NET NUMBER of each of these atoms in the cubic lattice. Also determine the MOLECULAR FORMULA.
Net X atoms: ?
Net Y atoms: ?
Net Z atoms: ?
Molecular Formula?
A cubic lattice has the atom X at teach of the corners, Y on each face center, and Z on each edge center. Determine the NET NUMBER of each of these atoms in the cubic lattice. Also determine the MOLECULAR FORMULA.
Net X atoms: ?
Net Y atoms: ?
Net Z atoms: ?
Molecular Formula?
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Each atom at a corner of the unit cell counts as 1/4 of an atom. Since there are 8 corners then (1/4 atom/corner)(8 corners) = 2 atoms total in the unit cell
Each atom on a face of a cube occupies (1/2 atom/face)(6 faces) = 3 atoms in the unit cell.
Each atom on the edge center of a cube will occupy (1/4 atom/edge)(12 edges) = 3 atoms in the unit cell.
This would give you a molecular formula of X2Y3Z3
Hope this is helpful to you. JIL HIR
Each atom on a face of a cube occupies (1/2 atom/face)(6 faces) = 3 atoms in the unit cell.
Each atom on the edge center of a cube will occupy (1/4 atom/edge)(12 edges) = 3 atoms in the unit cell.
This would give you a molecular formula of X2Y3Z3
Hope this is helpful to you. JIL HIR
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But the answer is wrong! Atoms on the corner count ⅛ so it is XY3Z3 which is strange (not fcc). I usually leave questions for 3 h before answering, but I spotted this error immediately.
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