Uhhh Chem help..IDK y i am so lost...
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Uhhh Chem help..IDK y i am so lost...

[From: ] [author: ] [Date: 11-09-05] [Hit: ]
the number of ligands will be double the positive charge on the metal ion.This doesnt always work (for example Co^2+ can form [Co(NH3)6]^2+) but it usually works.......
A simple reaction between Zn2+ and Ammonia NH3 will give me .....Zn[NH3}2+ right??????? and would that be my ionic equation?

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I would think it would be [Zn(NH3)4]^2+ and that the ionic equation would be

Zn^2+ + 4 NH3 -----------> [Zn(NH3)4]^2+

As a very general rule, the number of ligands will be double the positive charge on the metal ion. This doesn't always work (for example Co^2+ can form [Co(NH3)6]^2+) but it usually works.

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Zn2+(aq) + 2NH3(aq) + 2H2O ===> Zn(OH)2(s) + 2NH4+(aq)
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