What is the balanced equation for the titration of potassium permanganate (KMnO4) and Iron (II) "Fe+2" ?
Thanks.
Thanks.
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Adding the half-equations:
OXIDATION: Fe^2+(aq) → Fe^3+(aq) + e‾
REDUCTION: MnO4^-(aq) + 8H^+(aq) + 5e‾ → Mn^2+(aq) + 4H2O(l)
so as to eliminate electrons (ie 5 * OXIDATION + REDUCTION) we get the net ionic equation:
5Fe^2+(aq) + MnO4^-(aq) + 8H^+(aq) → 5Fe^3+(aq) + Mn^2+(aq) + 4H2O(l)
OXIDATION: Fe^2+(aq) → Fe^3+(aq) + e‾
REDUCTION: MnO4^-(aq) + 8H^+(aq) + 5e‾ → Mn^2+(aq) + 4H2O(l)
so as to eliminate electrons (ie 5 * OXIDATION + REDUCTION) we get the net ionic equation:
5Fe^2+(aq) + MnO4^-(aq) + 8H^+(aq) → 5Fe^3+(aq) + Mn^2+(aq) + 4H2O(l)
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The balanced chemical reaction would be
2KMnO4 + Fe2+ ---> 2K+ + Fe(MnO4)2
hope tha helped
2KMnO4 + Fe2+ ---> 2K+ + Fe(MnO4)2
hope tha helped