A mixture of three gases contains .50 mol of gas A, 1.00 mol of gas B, and 1.50 mol of gas C. If the mixture is contained in a 25.0 cylinder at 50 degrees Celsius, what is the total pressure of the mixture?
a. 49.9 kPa
b. 214 kPa
c. 322 kPa
a. 49.9 kPa
b. 214 kPa
c. 322 kPa
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If that 25.0 cylinder is in liters:
PV = nRT
moving variables around P = nRT/V
P = (3 mol)(0.082 atm-L/mol-K)(323) K)/(25.0 L)
P = 3.2 atm
P = 322 kPa
The answer is C.
PV = nRT
moving variables around P = nRT/V
P = (3 mol)(0.082 atm-L/mol-K)(323) K)/(25.0 L)
P = 3.2 atm
P = 322 kPa
The answer is C.