Class 11th chemistry doubt...plz plz plz help
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Class 11th chemistry doubt...plz plz plz help

[From: ] [author: ] [Date: 11-05-14] [Hit: ]
.-1st H2SO4 solution has density = 1.thats is 1ml has 1.218g substance. So, 1litre will have 1218g substance.......
Calculate the molarity, molality, and density of a solution prepared by mixing equal volumes of 30% by mass of H2SO4 whose density is 1.218g/mL & by 70% mass of H2SO4 of density 1.61 g/mL so that the resulting solution is 52.83% by mass.

This doubt is from the first chapter of chemistry i e Some basic concepts of Chemistry and is from the topic concentration of solution which involves:-
1)Mass %
2)Mass/Volume%
3)Molarity
4)Molality
5)Strength
6)Mole fraction

Please answer quickly....it is really urgent..and please stick to the 11th syllabus and explain how you have done it....

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1st H2SO4 solution has density = 1.218g/ml
thats is 1ml has 1.218g substance. So, 1litre will have 1218g substance. Now, H2SO4 in this 1 litre will be 30% by mass ie 0.3 x 1218 = 365.4g ie 365.4/98 moles H2SO4 = 3.73moles.
2nd H2SO4 solution has density = 1.61g/ml
thats is 1ml has 1.61g substance. So, 1litre will have 1610g substance. Now, H2SO4 in this 1 litre will be 70% by mass ie 0.7 x 1610 = 1127g ie 1127/98 moles H2SO4 = 11.5moles.
On mixing the solutions the total moles of H2SO4 become = 11.5 + 3.73 = 15.23 moles in 2 litres
So, Molarity = 15.23/2 = 7.615M
Now this molarity has 7.615 moles of H2SO4 in 2 litres ie 100% H2SO4. If this solution had to be 52.83% by mass then we must divide the total mass by 0.5283 ie (365.4 +1127) / 0.5283 = 2825g in 2000 ml. So in 1ml amount of substance will be 2825/2000 = 1.412 g/ml ie density of solution.
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