Emprical formula of 2.45g of silicon combined with 12.4g cl.
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Emprical formula of 2.45g of silicon combined with 12.4g cl.

[From: ] [author: ] [Date: 11-05-14] [Hit: ]
4/35.5 g/mole=0.......
Moles Si = 2.45 / 28.08 g/mol = 0.0873 mol (Grams / Molar Mass)
Moles Cl = 12.4 g / 35.5 g/mol = 0.349 mol (Grams /Molar Mass)

0.0873 / 0.0873 = 1 => Si
0.349 / 0.0873 = 4 => Cl

The Empiral formula is 1:4

The Compound is SiCl4

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determines moles of each element:
Si: 2.45 g/28.09 g/mole= 0.087
Cl: 12.4/35.5 g/mole= 0.349
mole ratio: 1 Si: Cl 4
SiCl4

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SiCl4
1
keywords: with,of,12.4,cl,silicon,formula,Emprical,2.45,combined,Emprical formula of 2.45g of silicon combined with 12.4g cl.
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