Balance using the half-reaction method
Favorites|Homepage
Subscriptions | sitemap
HOME > Chemistry > Balance using the half-reaction method

Balance using the half-reaction method

[From: ] [author: ] [Date: 11-05-14] [Hit: ]
Keep on Truckin!!......
Cu^2+ + I^- --> CuI + I3^-

I'm not sure how to divide this into two separate reactions?
Please explain.

-
It's tricky.

Try the following:

Cu^2+ + I^- + e^- --> CuI
3 I^- --> I3^- + 2 e^- >>> Start with 2 I^- --> I2 + 2 e^- then add I^- to react with I2 producing the more stable I3^-. Now, multiply the 1st reaction by 2 to obtain the correct numbers of electrons lost and gained. Then add the two half-reactions algebraically.

2 Cu^2+ + 2 I^- + 2 e^- --> 2 CuI
3 I^- --> I3^- + 2 e^-
-------------- ------------------- -----------
2 Cu^2+ + 5 I^- --> 2 CuI + I3^-

That's how you do it.

Keep on Truckin!!
1
keywords: method,the,reaction,using,Balance,half,Balance using the half-reaction method
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .