Here is the problem...What is the volume of 1.00 mol of a gas at room conditions ( 25c & 1.00 atm ).
The answer I have is 24.466 ( L??)
Hopefully this is correct - can anyone confirm?
Thanks!!
The answer I have is 24.466 ( L??)
Hopefully this is correct - can anyone confirm?
Thanks!!
-
V = nRT/p = (1.00 mole)(0.08206 L*atm/K*mole)(298 K)/(1.00 atm) = 24.454 L
Your answer seems to be a bit high. Did you calculate the Kelvin temperature correctly? The value I have given is the correct value.
Hope this helps you. JIL HIR
Your answer seems to be a bit high. Did you calculate the Kelvin temperature correctly? The value I have given is the correct value.
Hope this helps you. JIL HIR