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Easy Gas Laws Question Help

[From: ] [author: ] [Date: 11-05-14] [Hit: ]
all the help is greatly appreciated.How many liters of water vapor can be made from 55.0 grams of oxygen gas and an excess of hydrogen gas at a pressure of 12.4 atm and a temperature of 85.4 degrees Celsius?Since there is an excess of H2,......
Hi, I just need a little help with this homework problem. If you could show the steps that would be awesome. Thanks a lot, all the help is greatly appreciated.

How many liters of water vapor can be made from 55.0 grams of oxygen gas and an excess of hydrogen gas at a pressure of 12.4 atm and a temperature of 85.4 degrees Celsius?

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H2 + O2 ---> 2H20


Since there is an excess of H2, O2 is the limiting reactant and will determine the number of moles of water vapor in the product.


moles, O2 = mass / molecular weight = 55.0 g / (32.0 g/mol) = 1.71875 moles of O2

1.71875 moles O2 x (2 moles H2O / 1 mole O2) = 3.4375 moles of H2O



We can now solve for the volume (liters of water vapor) by using the ideal gas equation:


pV = nRT

(12.4 atm)(V) = (3.4375 moles)(.082057 L atm  / K  mol)(358.4 K)

V = 8.15 L



Hope this helps...good luck!
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