Benzaldehyde undergoes a reaction catalysed by cyanide ions to produce benzoin. 2 Molecules of benzaldehyde produces one molecule of benzoin. If 18.3g of benzaldehyde is used and the percent yield is 30.9%, how many grams of benzoin would be produced? The molar mass of benzaldehyde is 106.12 and for benzoin is 212.24.
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Calculate what you would get if you had an 100% yield, then multiply that result by 0.309.
18.3 g / 106.12 g/mol = 0.172 mol benzaldehyde --> 0.0862 mol benzoin
0.0862 mol * 212.24 g/mol = 18.3 g benzoin at 100% yield.
18.3 g * 0.309 = 5.65 g benzoin at 30.9% yield.
18.3 g / 106.12 g/mol = 0.172 mol benzaldehyde --> 0.0862 mol benzoin
0.0862 mol * 212.24 g/mol = 18.3 g benzoin at 100% yield.
18.3 g * 0.309 = 5.65 g benzoin at 30.9% yield.