Chem 11 Lab question major needing of help ....

I did half of the work sheet but there are just some questions that I don't understand and would really love your help on!! here they are:

Suppose you wanted to add just enough 0.40M calcium chloride (Ca Cl subscript 2) solution to 75.0 mL of 0.60M sodium carbonate (Na sub 2 CO sub 3) solution for all of the sodium carbonate and calcium chloride to react.
a) what volume of 0.40M calcium chloride solution would be required?
b) what mass of calcium carbonate would be produced (assuming 100% yield)?
c) what mass of sodium chloride would be produced (assuming a 100% yield)?
these questions are based on the chemical reaction of Ca Cl2 +Na2CO3(aq) => CaCO3 + 2NaCl(aq)
thank you so much to whoever would try to help! my brain is literally on a break....:(

75.0 mL of Na2CO3 x 0.60 mol/liter = 45 millimoles of Na2CO3 (0.045 mole)
Na2CO3 + CaCl2 --> CaCO3 + 2NaCl
1 mole Na2CO3 reacts with 1 mole CaCl2 to yield 1 mole CaCO3 and 2 mole NaCl
0.045 mole Na2CO3 reacts with 0.045 mole CaCl2 to yield 0.045 mole CaCO3 and 0.090 mole NaCl

a) ? mL CaCl2 solution x 0.40 mol/L = 45.0 millimole;
112.5 mL CaCl2 0.40 M solution
b) 0.0450 mole CaCO3 x 100.09 g/mole = 4.50 g CaCO3
c) 0.090 mole NaCl x 58.44 g/mole = 52.6 g NaCl