What is the equivalent resistance of a 15.0 ohm and a 26.0 ohm resistor connected in series? How much current would a 12.0 battery deliver to the resistor network, and what is the voltage drop across each resistor? Any work accompanying this would be great
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Garret's answer is wrong. The total resistance is 15 + 26 = 41 ohms. (His answer is right if the resistors were in parallel.) The current is 12 / 41 = 0.293 amps, and the voltage drops are I * R:
.293 * 15 = 4.39 volts
.293 * 26 = 7.61 volts
(These add up to 12.0 volts.)
.293 * 15 = 4.39 volts
.293 * 26 = 7.61 volts
(These add up to 12.0 volts.)
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Equiv. Res. of resistors in series can be found by: (R1+R2)to the negative 1). So the ER would be 9.5121 ohms. The Current would be equal in the two resistors. The equation V=IR (voltage=Current x Resistance) is what you should use. You would change it to I=R/V. so, you would do I=12/9.5121. which equals 1.2615 amps.