find all the zeros of the following polynomial function. Show all work.
f(x) = x^4 + x^3 + -11x^2 + 9x + 18
thanks a lot!!!
f(x) = x^4 + x^3 + -11x^2 + 9x + 18
thanks a lot!!!
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I think you might have made a sign error. That problem doesn't factor very nicely, but the similar problem:
f(x) = x^4 + x^3 + -11x^2 - 9x + 18
(note the - 9x instead of + 9x) has some nice solutions.
If this is the case, then you can proceed by trying out values with synthetic division and the rational root test.
In the source I give a link to a synthetic division calculator that will show all of the steps for each division. If you do the work correctly, you will find that the original function
f(x) = x^4 + x^3 + -11x^2 - 9x + 18
factors nicely as
f(x) = (x-3) (x-1) (x+2) (x+3)
which has zeros at:
x = 3
x = 1
x = -2
x = -3
Hope this helps!
f(x) = x^4 + x^3 + -11x^2 - 9x + 18
(note the - 9x instead of + 9x) has some nice solutions.
If this is the case, then you can proceed by trying out values with synthetic division and the rational root test.
In the source I give a link to a synthetic division calculator that will show all of the steps for each division. If you do the work correctly, you will find that the original function
f(x) = x^4 + x^3 + -11x^2 - 9x + 18
factors nicely as
f(x) = (x-3) (x-1) (x+2) (x+3)
which has zeros at:
x = 3
x = 1
x = -2
x = -3
Hope this helps!
-
Im not an expert on polynomials, but as this is a 4th or ^4 function.
The polynomial should cross the zero point 4 times.
You could always use (MathCad) to plot this into a graph to show the function.
The polynomial should cross the zero point 4 times.
You could always use (MathCad) to plot this into a graph to show the function.