Physics, Mars problem, please help

In the long jump, an athlete launches herself at an angle above the ground and lands at the same height, trying to travel the greatest horizontal distance. Suppose that on earth she is in the air for time , reaches a maximum height , and achieves a horizontal distance .

A = If she jumped in exactly the same way during a competition on Mars, where is 0.379 of its earth value, find her time in the air. Express your answer in terms of t of M = t.

B = If she jumped in exactly the same way during a competition on Mars, where is 0.379 of its earth value, find her maximum height. Express your answer in terms of h of M = h.

C = If she jumped in exactly the same way during a competition on Mars, where is 0.379 of its earth value, find her horizontal distance. Express your answer in terms of D of M = D.

I know this might be very easy but physics is really hard for me. Please help, thank you

Need to use kinematic equations for all the problems.

First off, she is running at a velocity v, then jumps. At this point, she has a y-component of velocity and an x-component of velocity. Since we don't seem to be accounting for other forces, I guess we're assuming she's in a vacuum! :P

Alright, use the kinematic equation: acceleration * time = final velocity - initial velocity

For the first half of the parabola, final velocity will be 0, and acceleration is -9.81 m/s^2...or just -g

So...the first half of the parabola is t = initial velocity / g [keep in mind that these are for the y-component of velocity]

The second time is very similar, except we start with the final velocity as the negative of the initial velocity (in the beginning) and for this second half of the parabola, she'll be starting at v = 0

Overall, t = 2 * initial velocity[y-component] / g

To make it simpler, let v = initial velocity. Using trig, v*sin(theta) = y component of the velocity, where theta is of course the angle above the ground.