A rope is used to pull a 3.57 kg block at constant speed 3.66 m along a horizontal floor. The force on the block from the rope is 7.46 N and is directed 15° above the horizontal.
(c) What is the coefficient of kinetic friction between the block and floor?
I did 7.46*cos(15)/3.5(9.8)....
nope...
(c) What is the coefficient of kinetic friction between the block and floor?
I did 7.46*cos(15)/3.5(9.8)....
nope...
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Vertical component of applied force = (sin 15 x 7.46) = 1.931N.
Normal force = (3.57 x g) - 1.931 = 33.055N.
Horizontal component = (cos 15 x 7.46) = 7.2N. This is all friction (because of the steady speed).
µK = (7.2/33.055) = 0.218.
Normal force = (3.57 x g) - 1.931 = 33.055N.
Horizontal component = (cos 15 x 7.46) = 7.2N. This is all friction (because of the steady speed).
µK = (7.2/33.055) = 0.218.