- remember this is only for the ball going down. So multiply by two = 1.206408 secs total.
- Now lets find out the total amount of time th ball took to go up from the building and then down to the ground.
-Remember that when the ball is going up it is also moving forward with the velocity in the x direction at 5.9114 m/s therefore since it moved 13.8 m away we can find the total time.
- v= distance / time. We have V and Distance so t = distance / velocity x direction.:
- T = 13.8/ 5.9114 = 2.3345 secs TOTAL
- but we are only interested in the time that the ball is falling starting from the top of the building to the ground so subtract the time it took the ball to go up and down to the top of the building in the beginning from the total time:
2.3345 - 1.206408 = 1.128 secs
Since we have the time it took for the ball to fall from the top of the building to the bottom lets find the height with the equation:
D = Vit + .5 a t^2
The Initial velocity we know is 5.9114 m/s
The time is 1.128 secs SO FIND D
D = 12.9 m