How to calculate the potential difference between plates
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How to calculate the potential difference between plates

[From: ] [author: ] [Date: 12-12-04] [Hit: ]
So capacitance is C = εo*A / d = 8.85*10^-12 * 0.2 / 0.005 F = 3.V = Q / C = 0.5*10^-6 C / 3.......
A pair of parallel conducting plates each 40cm x 50cm have a separation of 5mm and carry charges of ±5CµC. Calculate the potential difference between the plates.

I have a problem on how to get the permittivity of the dielectric too.

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There is only enough information to derive the potential difference OR the permittivity but not both independently.

So we must assume the dielectric is air, with permittivity εo.

Plate area A = 0.4m*0.5m = 0.2m^2

So capacitance is C = εo*A / d = 8.85*10^-12 * 0.2 / 0.005 F = 3.54*10^-10 F

Potential difference is therefore

V = Q / C = 0.5*10^-6 C / 3.54*10^-10 F

V = 1410 Volts
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