This is the question (X±3)4 in other words x plus 3 to the 4th power its algebra 2 math i need the steps because i have no idea how to do it
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You use Pascal's triangle to get the coefficients of each term. Since it is to the 4th power, you look at the 4th row of Pascal's triangle. The coefficients are 1,4,6,4,1 and are all positve.
So, the answer is 1x^4(3^0) + 4x^3(3^1) + 6x^2(3^2) + 4x^1(3^3) + 1(x^0)3^4
I put in all the terms (even those things raised to the 0 power) so that you could see that the powers of x go from 4 down to 0
and the powers of 3 go from 0 up to 4.
So, the answer is 1x^4(3^0) + 4x^3(3^1) + 6x^2(3^2) + 4x^1(3^3) + 1(x^0)3^4
I put in all the terms (even those things raised to the 0 power) so that you could see that the powers of x go from 4 down to 0
and the powers of 3 go from 0 up to 4.
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You can use Pascal's triangle to get the coefficients of each term. Since it is to the 4th power, you look at the 4th row of Pascal's triangle. The coefficients are 1,4,6,4,1 and are all positve.
Your answer is 1x^4(3^0) + 4x^3(3^1) + 6x^2(3^2) + 4x^1(3^3) + 1(x^0)3^4
Your answer is 1x^4(3^0) + 4x^3(3^1) + 6x^2(3^2) + 4x^1(3^3) + 1(x^0)3^4
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look up pascals triangle it helps A LOT trust me. but it would be x^4+18x^3+99x^2+162x+81
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word of advice, don't waste your time with this crap. Distribution is used to make things simpler. Exponents are used to make things simpler. Making things more difficult is pointless.