8.45×10^-5 M K2O
6.40×10^-2 M HBr
5.84×10^-5 M Sr(OH)2
6.40×10^-2 M HBr
5.84×10^-5 M Sr(OH)2
-
-log(8.45×10^-5 M) = 4.07
-log(6.40×10^-2 M) = 1.19
The last one is a little bit more tricky bc if we do the same -log we will get the POH instead of PH.
But finding the PH is as simple as substracting the POH from 14.
-log(5.84×10^-5 M) = 4.23
14-4.23 =9.77
-log(6.40×10^-2 M) = 1.19
The last one is a little bit more tricky bc if we do the same -log we will get the POH instead of PH.
But finding the PH is as simple as substracting the POH from 14.
-log(5.84×10^-5 M) = 4.23
14-4.23 =9.77